Hackerrank Python: How to code python in hackerrank


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Hackerrank Python | Hackerrank Python Solutions | Python Hackerrank | Hackerrank Interview Questions | Hackerrank Challenge


Nowadays, It’s very tough for companies to hire a candidate through the normal interview process. There is a vast number of candidates interviewed daily for python programming and other programming languages. It kills a lot of time to conduct a traditional interview process and filter out the required candidate. It takes lots of time and effort for both candidates and the hiring companies. As a result, Hackerrank comes into the picture. Hackerrank Python(Hackerrank Challenge) provides a platform and portal to conduct an online test.

Hackerrank tests are conducted by many companies Hackerrank for python programming, .Net, Java, etc. It makes the quality hiring process flexible and efficient. We are going to discuss in-depth details about the Hackerrank Python test and python programming. How this is conducted, what all things happen in Hackerrank Python online test, and other details.


Python features Dynamic Type System and Automatic Memory Management. It is suitable for general tasks, General Level Purpose, High-Level Programming language, Interactive, Object Oriented, Scripting language. It supports multiple programming paradigms and has an extensive and comprehensive standard library. In this blog, We will discuss the Python and Hackerrank Python test in detail.

Python is typically used for complex web applications, server-side python programming, or large e-commerce systems that provide web services. Python has become a preferred language in Machine Learning, Artificial Intelligence, and Big Data Technology.

If you want a career as a software developer, then you should be well versed in Python. Python Programmers are always in demand, as Python is a modern programming language, which is currently high in demand. Companies choose to develop their software in python programming instead of another programming language to develop their software.

History of Python Programming

Python was designed in the late 1980s. Its implementation began in December 1989. Guido Van Rossum built Python from 1985–1990 in the Netherlands.

The first version of Python (1.0) was released in January 1994, its second version (2.0) was released on October 16, 2000, the third version of Python was released on December 3, 2008, after a long period. It was not compatible with Python 2.x. Now version 3.7 of Python is running, which was released on June 27, 2018.

OverView Hackerrank Python (Hackerrank Challenge)

HackerRank Python, a forum for assessing developer abilities in the planning of interviews, is among the best tools for checking the coding skills online.

A vast part of the website is devoted to coding Python HackerRank test and has a sub-set dedicated to checking your Python skills.

Let us discuss some popular Hackerrank Python questions.

Hackerrank Python Solution for Problem: Kangaroo

Today we will solve “Kangaroo” a beginners level problem from HackerRank using python. I hope this would help you, Share with me if you got any better solution.

Problem: Hackerrank Challenge

You are choreographing a circus show with various animals. For one act, you are given two kangaroos on a number line ready to jump in the positive direction (i.e, toward positive infinity).

  • The first kangaroo starts at location  x1 and moves at a rate of v1 meters per jump.
  • The second kangaroo starts at location x2  and moves at a rate of v2 meters per jump.

You have to figure out a way to get both kangaroos at the same location at the same time as part of the show. If it is possible, return YES, otherwise return NO.

For example, kangaroo 1 starts at  x1 = 2 with a jump distance v1 = 1  and kangaroo 2  starts at x2 = 1  with a jump distance of v2 = 2 . After one jump, they are both atx = 3  , (x1 + v1 = 2+1, x2 + v2 = 1+2 ), so our answer is YES.

Function Description

Complete the function kangaroo in the editor below. It should return YES if they reach the same position at the same time, or NO if they don’t.

kangaroo has the following parameter(s):

  • x1, v1: integers, starting position and jump distance for kangaroo 1
  • x2, v2: integers, starting position and jump distance for kangaroo 2

Input Format

A single line of four space-separated integers denoting the respective values of x1,v1 ,x2 , and v2.


  • 0<= x1 < x2 <= 10000
  • 1<= v1 <= 10000
  • 1<= v2 <= 10000

Output Format

Print YES if they can land on the same location at the same time; otherwise, print NO.

Note: The two kangaroos must land at the same location after making the same number of jumps.

Sample Input

0 3 4 2

Sample Output



The two kangaroos jump through the following sequence of locations:


From the image, it is clear that the kangaroos meet at the same location (number  on the number line) after same number of jumps ( jumps), and we print YES.

Sample Input

0 2 5 3

Sample Output


Hackerrank Python Explanation

The second kangaroo has a starting location that is ahead (further to the right) of the first kangaroo’s starting location (i.e., x2 > x1). Because the second kangaroo moves at a faster rate (meaning v2 > v1) and is already ahead of the first kangaroo, the first kangaroo will never be able to catch up. Thus, we print NO.

Solution code for Hackerrank Python Kangaroos Problem

Let us see the python programming for this problem. You can test this code in your local python configured machine.

import math
import os
import random
import re
import sys
# Complete the kangaroo function below.
def kangaroo(x1, v1, x2, v2):
    if x2 > x1 and v2 > v1:
        return "NO"
        if v2-v1 == 0:
            return 'NO'
            result = (x1-x2) % (v2-v1)
            if result == 0:
                return 'YES'
                return 'NO'

if __name__ == '__main__':
    fptr = open(os.environ['OUTPUT_PATH'], 'w')
    x1V1X2V2 = input().split()
    x1 = int(x1V1X2V2[0])
    v1 = int(x1V1X2V2[1])
    x2 = int(x1V1X2V2[2])
    v2 = int(x1V1X2V2[3])
    result = kangaroo(x1, v1, x2, v2)
    fptr.write(result + '\n')

No Idea in python – Hackerrank Python Problem


There is an array of n integers. There are also 2 disjoint sets, A and B, each containing m integers. You like all the integers in set A and dislike all the integers in set B. Your initial happiness is 0. For each i integer in the array, if i (- A , you add 1 to your happiness. If i (- B, you add -1 to your happiness. Otherwise, your happiness does not change. Output your final happiness at the end.

Note: Since A and B are sets, they have no repeated elements. However, the array might contain duplicate elements.

Constraints :

  • 1 <= n <= 10^5
  • 1 <= m <= 10^5
  • 1 <= any integer in the input <= 10^9

Input Format

The first line contains integers n and m separated by a space.
The second line contains n integers, the elements of the array.
The third and fourth lines contain m integers, A and B, respectively.

Output Format

Output a single integer, your total happiness.

Sample Input

<strong>3</strong> <strong>2</strong>
<strong>1</strong> <strong>5</strong> <strong>3</strong>
<strong>3</strong> <strong>1</strong>
<strong>5</strong> <strong>7</strong>

Sample Output



You gain 1 unit of happiness for elements 3 and 1 in set A. You lose 1 unit for 5 in set B. The element 7 in set B does not exist in the array so it is not included in the calculation.
Hence, the total happiness is 2 – 1 = 1.


Let us see the python programming for this problem. You can test this code in your local python configured machine.

# Hackerrank Python Solution- No Idea in python
# Enter your code here. Read input from STDIN. Print output to STDOUT
# No Idea in python - Hackerrank Python Solution  START
io = input().split()
m = int(io[0])
n = int(io[1])
storage = list()
count = 0
storage = list(map(int, input().strip().split()))
A = set(map(int, input().strip().split()))
B = set(map(int, input().strip().split()))
for i in storage:
    if i in A:
        count = count+1
    if i in B:
        count = count-1

FizzBuzz- Hackerrank Python Problem(Hackerrank Challenge)


Fizz Buzz is a very simple programming task, asked in software developer job interviews.

A typical round of Fizz Buzz can be: 
Write a program that prints the numbers from 1 to 100 and for multiples of ‘3’ print “Fizz” instead of the number and for the multiples of ‘5’ print “Buzz”. 

1, 2, Fizz, 4, Buzz, Fizz, 7, 8, Fizz, Buzz, 11, Fizz, 13, 14, 
Fizz Buzz, 16, 17, Fizz, 19, Buzz, Fizz, 22, 23, Fizz, Buzz, 26, 
Fizz, 28, 29, Fizz Buzz, 31, 32, Fizz, 34, Buzz, Fizz, ...


Let us see the python programming for this problem. You can test this code in your local python configured machine.

def fizzBuzz(n):
    for i in range(1,n+1):
        if i % 3 == 0 and i % 5 == 0:
        elif i % 3 == 0:
        elif i % 5 == 0:

Also Read: Modern Web Design: Transit from Traditional Approach

Minimum Time Required: Python Hackerrank Challenge

First I tried to make the right assessment of the typical system productivity and to apply one day at a time. This lead to a runtime mistake.

We need to do binary searches to do better than beginning the best quest. I set the best guess to the lower limits and the top limits to the lower limits plus the slowest machine time. It means that we have found the minimum time that the two borders cross.

I have used one trick by putting the lower border on the best guess minus 1, so we don’t launch our best response from the lower border. We will always return the upper limit as the best answer in my code below.


time: 0(mlogt) where m is the number of machines, and t is maximum value of machines’ time.

memory: o(1)


Let us see the python programming for this problem. You can test this code in your local python configured machine.

def minTime(machines, goal): 
    # make a modest guess of what the days may be, and use it as a starting point
    efficiency = [1.0/x for x in machines]
    lower_bound = int(goal / sum(efficiency)) - 1
    upper_bound = lower_bound + max(machines) + 1
    while lower_bound < upper_bound -1:
        days = (lower_bound + upper_bound)//2
        produce = sum([days//x for x in machines])
        if produce >= goal:
            upper_bound = days
        elif produce < goal:
            lower_bound = days
    return upper_bound

Some useful links



How to take input in hackerrank python?

input() method is used to take input in python

Which is the most popular hackerrank python portal(Hackerrank Challenge)?

Is it mandatory to take this test in all companies?

No, It’s not mandatory as only some companies hire through Hackerrank Python test for python programming.

What is the qualifying marks in python programming online test for python programming?

It depends on number of questions and evaluation process. Mostly 50-60% is considered to be good score.

Closing Notes

I think you must have liked this article. If you have any doubt, please comment or mail me. I have tried o cover most of things. Any suggestion is always welcome.

Also Read: Learn ASP.NET Core Programming

Raushan Kumar
A Cook, Software analyst & Blogger.


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